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4x² + 4x +1 + 32y² +128y + 128 = 1+128-65
4(x²+x+1/4)+32(y²+4y+4)=64
dividiendo
(x+1/2)² +(y+2)² = 1
16 2
por tanto: a = 4
b = √2
c(h;K) = (-1/2 ; -2)