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a) f(x)∈(-3; 5>
obl. f(x)=-3 i f(x)=5
-2x+3= -3 -2x+3=5
-2x=-6 -2x=2
x=3 x=-1
odp Dla x∈< -1; 3) f(x)∈(-3; 5>
B) f(x)∈ (-5 1/3; 1/2)
obl f(x)=-5 1/3 i f(x)=1/2
-2x+3=-5 1/3 -2x+3=1/2
-2x=-8 1/3 /: (-2) -2x=-2 1/2
x=4 1/6 x=1 1/4
odp dla x∈ (1 1/4; 4 1/6)
c) f(x)=1-2√2 f(x)=o
-2x+3= 1-2√2 -2x+3=0
-2x=-2-2√2 x=3/2
-2x=-2(1-√2) /:(-2)
x=1-√2
odp dla x∈<1-√2; 1 1/2>