Question

2 buah muatan masing-masing q1 = 6 mc, q2 = 12 mc terpisah sejauh 3 cm. Tentukan besar gaya yang terjadi antara 2 muatan tersebut!

Bantu secepatnya! ​

Answer 1

Penjelasan:

Dik :

q1 = 6 μC = 6 × 10^-6

q2 = 12μC = 12 × 10^-6

r = 3 Cm = 0,03 m = 3 × 10^-2 m

k = 9 × 10⁹ Nm²/C²

Dit : Gaya Coulomb (F)

Jawab :

[tex]F = \: k \frac{ q_{1}q _{2} }{ {r}^{2} } [/tex]

[tex]F = \: 9 \times {10}^{9} \frac{6 \times {10}^{ - 6} \times 12 \times {10}^{ - 6} }{ {( {3 \times 10}^{ - 2} )}^{2} } [/tex]

[tex]F = \: \frac{9 \times 6 \times 12 \times {10}^{9 - 6 - 6} }{9 \times {10}^{ - 4} } [/tex]

[tex]F \: = \frac{648 \times {10}^{ - 3} }{9 \times {10}^{ - 4} } [/tex]

[tex]F = \: \bold{720 \: n}[/tex]