Odpowiedź:
[tex]a=-0,5=-\frac{5}{10}=-\frac{1}{2} \\ b=3\frac{1}{3} =\frac{10}{3}\\ (-0,6a^2b)^2=(-\frac{6}{10}*(-\frac{1}{2})^2*\frac{10}{3} )^2=(-2*\frac{1}{4})^2= (-\frac{1}{2})^2=\frac{1}{4} \\\\b)\\(-\frac{1}{x}+x^3)^2*\frac{8}{25} =(-\frac{1}{-\frac{1}{2}}+(-\frac{1}{2})^3)^2*0,32=(2-\frac{1}{8})^2*0,32=(\frac{15}{8} )^2*\frac{32}{100} =\frac{225}{64}* \frac{32}{100} =\frac{9}{2}*\frac{1}{4} =\frac{9}{8} =1\frac{1}{8}[/tex]
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Odpowiedź:
[tex]a=-0,5=-\frac{5}{10}=-\frac{1}{2} \\ b=3\frac{1}{3} =\frac{10}{3}\\ (-0,6a^2b)^2=(-\frac{6}{10}*(-\frac{1}{2})^2*\frac{10}{3} )^2=(-2*\frac{1}{4})^2= (-\frac{1}{2})^2=\frac{1}{4} \\\\b)\\(-\frac{1}{x}+x^3)^2*\frac{8}{25} =(-\frac{1}{-\frac{1}{2}}+(-\frac{1}{2})^3)^2*0,32=(2-\frac{1}{8})^2*0,32=(\frac{15}{8} )^2*\frac{32}{100} =\frac{225}{64}* \frac{32}{100} =\frac{9}{2}*\frac{1}{4} =\frac{9}{8} =1\frac{1}{8}[/tex]
Szczegółowe wyjaśnienie: