Oblicz :
a) (-6√0.54 + 15√0.06) : √6
b) ( 6∛40 i 1/2 - 8∛12) : 2∛1,5
ma być to rozwiązane tym sposobem, np. (3√50 +2√8-√32) : √2 = 3√50:2+2√8:2-√32:2=3*5+2*2-4+15
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a) (-6√0.54 + 15√0.06) : √6 = -6√(0.54 : 6) + 15√(0.06 : 6) = -6 √0,09 + 15√0,01 = -6 * 0,3 + 15 * 0,1 = -1,8 + 1,5 = -0,3
b) ( 6∛40 i 1/2 - 8∛12) : 2∛1,5 = 3 ∛(40i1/2 : 1,5) - 4∛(12 : 1,5) =
3 ∛(81/2 * 10/15) - 4 ∛(12 * 10/15) = 3 ∛(81/2 * 2/3) - 4∛(12 * 2/3) = 3 ∛27 - 4 ∛8 =
3 * 3 - 4 * 2 = 9 - 8 = 1