Wyznacz wzór funkcji kwadratowej w postaci kanonicznej i ogólnej jeżeli:
a) W = (-3,0) i A = (-8,15)
b) W = (2,0) i A = (5,-6)
c) Δ = 12 i W=(4,3)
d) Δ = -8 i W=(1/2 , 1)
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a) y = a(x+3)^2
y=a(x^2+6x+9)
y=ax^2+6ax+9a
A=(-8,15) => 15 = 64a-48a-9a
7a=15 => a=15/7
y=15/7(x+3)^2
y=15/7x^2 + 90/7x+135/7
b) y=a(x-2)^2
y=ax^2-4ax+4a
A=(5,-6) => a=-2/3
y=-2/3(x-2)^2
y=-2/3x^2+8/3x-8/3
c)y= a(x-4)^2+3
y=ax^2-8ax+16a+3
delta=12
64a^2- 4a(16a+3)
a=1
y=(x-4)^2+3
y=x^2-8x+19
d) y=a(x-1/2)^2+1
y=ax^2-ax+1/4a+1
delta=-8
a^2-4a(1/4a+1)
a=-2
y=-2(x-1/2)^2+1
y= -2x^2+2x-3/2
nie jestem pewien tych 2 pierwszych