a)x(5x-2)-2x(x+1)=5x-2x-2x-2x=-1x
b)(a+2)²-(a-2)²=a²+2²-a²+2²=4²
c) (a+2b)(2a-b)-3ab=a+2b·2a-b-3ab=2a+b-3ab
d)(√a+2)(√a-2)-2(a²-1)=√a+2·√a-2-2a²+2=-2a+2
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Zad.1
a)
x(5x-2)-2x(x+1) =5x^2 -2x-2x^2 -2x =3x^2 - 4x
b)
(a+2)^2 -(a-2)^2 =a^2 +4a+4-(a^2 -4a+4) =a^2 +4a+4-a^2 +4a-4 = 8a
c)
(a+2b)(2a-b)-3ab = 2a^2 -ab+4ab-2b^2 -3ab = 2a^2 - 2b^2
d)
(a+V2)(a-V2)-2(a^2 -1) =a^2 -2 -2a^2 +2 = -a^2
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a)x(5x-2)-2x(x+1)=5x-2x-2x-2x=-1x
b)(a+2)²-(a-2)²=a²+2²-a²+2²=4²
c) (a+2b)(2a-b)-3ab=a+2b·2a-b-3ab=2a+b-3ab
d)(√a+2)(√a-2)-2(a²-1)=√a+2·√a-2-2a²+2=-2a+2
na 99% dobrze :)
Zad.1
a)
x(5x-2)-2x(x+1) =5x^2 -2x-2x^2 -2x =3x^2 - 4x
b)
(a+2)^2 -(a-2)^2 =a^2 +4a+4-(a^2 -4a+4) =a^2 +4a+4-a^2 +4a-4 = 8a
c)
(a+2b)(2a-b)-3ab = 2a^2 -ab+4ab-2b^2 -3ab = 2a^2 - 2b^2
d)
(a+V2)(a-V2)-2(a^2 -1) =a^2 -2 -2a^2 +2 = -a^2