1)wyznacz ciąg geometryczny,jeśli a2=8 a5=64
2)wyznacz ciąg arytmetyczny jeśli a5=16 a7=40
1)
a₂ = 8
a₅ = 64
a₂ = a₁ x q
a₅ = a₁ x q⁴
a₁ x q = 8 => a₁ = 8/q
a₁ x q⁴ = 64
8/q x q⁴ = 64
8 x q³ = 64
q³ = 8
q = 2
a₁ x 2 = 8
a₁ = 4
an = 4 x 2^(n-1)
2)
a₅ = a₁ + 4r = 16
a₇ = a₁ + 6r = 46
a₁ + 4r = 16
a₁ + 6r = 46
------------------
2r = 30
r = 15
a₁ + 4*15 = 16
a₁ + 60 = 16
a₁ = -44
an = -44 + 15(n-1) = -44 + 15n - 15 = -59 + 15n
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Litterarum radices amarae sunt, fructus iucundiores
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1.
a2 = 8 , a5 = 64 ciąg geometryczny
q³ = a5/a2 = 64/8 = 8
q = ∛8 = 2
a2 = q*a1 /:q
2a1 = 8 /:2
a1 = 4
an = a1 * q^(n-1)
an = 4 *2^(n-1)
----------------------
2.
a5 = 16, a7 = 40 ciąg arytmetyczny
a5 = a1 + 4r = 16
a7 = a1 + 6r = 46
6r - 4r = 46 - 16
2r = 30 /:2
a1 + 4*15 = 16
a1 = 16 - 60
a1 = -44
an = a1 + (n-1)*r
an = -44 + (n-1) *15 = -44 + 15n - 15
an = 15n - 59
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1)
a₂ = 8
a₅ = 64
a₂ = a₁ x q
a₅ = a₁ x q⁴
a₁ x q = 8 => a₁ = 8/q
a₁ x q⁴ = 64
8/q x q⁴ = 64
8 x q³ = 64
q³ = 8
q = 2
a₁ x 2 = 8
a₁ = 4
a₁ = 4
q = 2
an = 4 x 2^(n-1)
2)
a₅ = a₁ + 4r = 16
a₇ = a₁ + 6r = 46
a₁ + 4r = 16
a₁ + 6r = 46
------------------
2r = 30
r = 15
a₁ + 4*15 = 16
a₁ + 60 = 16
a₁ = -44
an = -44 + 15(n-1) = -44 + 15n - 15 = -59 + 15n
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
1.
a2 = 8 , a5 = 64 ciąg geometryczny
q³ = a5/a2 = 64/8 = 8
q = ∛8 = 2
a2 = q*a1 /:q
2a1 = 8 /:2
a1 = 4
an = a1 * q^(n-1)
an = 4 *2^(n-1)
----------------------
2.
a5 = 16, a7 = 40 ciąg arytmetyczny
a5 = a1 + 4r = 16
a7 = a1 + 6r = 46
6r - 4r = 46 - 16
2r = 30 /:2
r = 15
a1 + 4*15 = 16
a1 = 16 - 60
a1 = -44
an = a1 + (n-1)*r
an = -44 + (n-1) *15 = -44 + 15n - 15
an = 15n - 59
------------------