1.Woda morska zawiera 5% soli. Z ilu kilogramów tej wody otrzymamy 20 kg soli?
2.Oblicz jakim procentem wielkości w jest a ,jeżeli :
a) w=3 godz , a=20min
b)w=11h , a=1h 6min
c)w=42 zł , a=2 zł 10gr
d)w=2,2 km , a=1210m
e) w=24cm , a= 0,6m
pełne zadania poproszę;)
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Zad.2
a)w=3h=180min
a=20min
20/180*100%=11,11%
b)w=11h=660min
a=1h 6min=66min
66/660*100%=10%
c)w=42zł=4200gr
a=2zł 10gr=210gr
210/4200*100%=5%
d)w=2,2km=2200m
a=1210m
1210/2200*100%=55%
e)w=24cm
a=0,6m=60cm
60/24*100%=250%
1. 20kg soli = 5%
x kg wody = 100%
x=20kg*100%/5%=400kg
2.
a) w=3godz.=180min
100%=180min
x%=20min
x%=100%*20min/180min=11,(1)%
b)w=11h=660min a=1h 6min=66min
100%=660min
x%=66min
x%=100%*66min/660=10%
c)w=42zł=4200gr a=2zł10gr=210gr
100%=4200gr
x%=210gr
x%=100%*210gr/4200gr=5%
d)w=2,2km=2200m
100%=2200m
x%=1210m
x%=100%*1210m/2200m=55%
e)a=0,6m=60cm
100%=24cm
x%=60cm
x%=100%*60cm/24cm=250%