1.Usuń nieymierność z mianownika ułamka i Podaj potrzebne zastrzeżenia
a) 2+x =
√5
b) 1-√3 =
a+√2
2. Wyznacz x:
a= b*(x - 2)
c+1
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a)
(2+x )/√5 = (2+x )/√5 * ( √5/√5) =[ √5(2 +x)]/5
b)
(1-√3)/(a+√2) = (1-√3)/(a+√2) * (a-√2) /(a-√2) =
= [(1-√3) (a-√2)] / (a² -2)
Zad.2
a = b(x-2) /(c+1) /* (c+1)
a(c+1) = b(x-2)
a(c+1) = bx -2b
bx = a(c+1) + 2b /:b
x = a(c+1)/b + b