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I = 0,25 [A]
t = 0,5 [h] = 1800 [s]
q = ?
I = q/t
q = I t
q = 0,25 × 1800
q = 450 [C]
2.
U1 = 220 [V]
P1 = 2000 [W]
U2 = 55 [V]
Najpierw obliczamy opór tej kuchenki (opór danej kuchenki (opornika) jest stały)
P1 = U1²/ R
R = U1² / P1
[om] = [V² / V A = V/A = om]
R = 24,2 [om]
Teraz liczymy drugą moc
P2 = U2² / R
[W] = [V² / om = V²/ V/A = VA = W]
P2 = 125 [W]
q=?
t= 0,5h= 30min= 1800s
I=q/t mnożymy przez t, więc:
q= I*t
q= 450 C (Coulomba)
2.
U= 220V
U₂= 55V
2000W- 220V
x- 55V
x= 500W