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a²=324
a=√324=18cm --->dl,boku kwadratu
wiadomo ze
1 bok 18+(x+1)
2 bok 18+2x
(18+x+1)/(18+2x)=5/6
6(19+x)=5(18+2x)
114+6x=90+10x
114-90=10x-6x
24=4x /:4
x=6cm
zatem boki otrzymamnego prostokata maja dlugosc:
1 bok 18+6+1=25cm
2 bok 18+2·6=18+12=30cm
zatem obwod prostokta wynosi:
O=2·25+2·30=50+60=110cm