1.Oblicz:
2√98:√2
2.Zapisz w prostrzej postaci.
a) -5(∛13-4)-6∛-13 =
2
b)2√72-½√50⁺√2³=
3.Usun niewymiernosci z mianownika ułamka
2√3+5
3√2
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W załącznikach.Liczę na Naj.
zad1
2√98:√2=√49=7
zad2
a)-5(∛13-4)-( 6∛3-13/2)=-5∛13+20-3√13=-8∛13+20 =-4(∛13-5)
b)2√72 -½√50+√2³=2√36·√2-½√25·√2+√8=12√2-2.5√2+2√2=11,5√2
zad3)
(2√3+5)/3√2 =(2√3+5)√2 / 3√2√2=(2√6+5√2) /6 =√6/3 + ⁵/₆√2