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mC4H9OH=4*12u+9*1u+16u+1u=74u
%C=46/74*100%=64,86%
2.
CnH2n+1 OH=102u
12n+2n+1+16+1=102
14n+18=102
14n=102-18
14n=84/:14
n=6
wzór sumaryczny C6H13OH
nazwa heksanol
wzór półstrukturalny CH3-(CH2)5-OH