1.Oblicz wartość liczbową wyrażenia : -3(2a-b) dla a = 4 , b = 3 2 . Usuń nawiasy i wykonaj redukcje wyrazów podobnych : a (-3a+z)+(5a-8) = b (2a+1)-(5-2a)= c 4(3x-6)+3(2+7x)= d 5(3z-7)-9(8z-6) = e 3 (6x-5) = 3 .Zamień sumę na iloczyn : a 12b+9 = b 10n-5 = c 63m+54n-9= d 3a+3 =
-3(2a-b) =
-6a+3b =
-6*4+3*3 =
-24+9 =
-15
2 .
a
(-3a+z)+(5a-8) =
-3a+z+5a-8 =
2a+z-8
b
(2a+1)-(5-2a)=
2a+1-5+2a =
4a-4
c
4(3x-6)+3(2+7x)=
12x-24+6+21x =
33x-18
d
5(3z-7)-9(8z-6) =
15z-35-72z+54 =
-57z+19
e
3 (6x-5) =
18x-15
3 .
a 12b+9 = 3(4b+3)
b 10n-5 = 5(2n-1)
c 63m+54n-9= 9(7m+6n-1)
d 3a+3 = 3(a+1)
-3(2a-b) =
-6a+3b =
-6*4+3*3 =
-24+9 =
-15
2 .
a
(-3a+z)+(5a-8) =
-3a+z+5a-8 =
2a+z-8
b
(2a+1)-(5-2a)=
2a+1-5+2a =
4a-4
c
4(3x-6)+3(2+7x)=
12x-24+6+21x =
33x-18
d
5(3z-7)-9(8z-6) =
15z-35-72z+54 =
-57z+19
e
3 (6x-5) =
18x-15
3 .
a 12b+9 = 3(4b+3)
b 10n-5 = 5(2n-1)
c 63m+54n-9= 9(7m+6n-1)
d 3a+3 = 3(a+1)
chyba tak
tak robilismy na lekcjii
to musi byc dobrze...
licze na naj!!!!!1