1)Oblicz stosunek wagowy wodoru do węgla w cząsteczce metanu
2) Oblicz skład procentowy metanu
1) mCH4=12u+4*1u=16u
mC : mH = 12 : 4
mC : mH = 3 : 1
2) mCH4=12u+4*1u=16u
%C = (12/16)*100% = 75% węgla
%H = (4/16)*100% = 25% wodoru
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1) mCH4=12u+4*1u=16u
mC : mH = 12 : 4
mC : mH = 3 : 1
2) mCH4=12u+4*1u=16u
%C = (12/16)*100% = 75% węgla
%H = (4/16)*100% = 25% wodoru