1) mC3H5(OH)3=36u+8u+48u=92umC : mH : mO = 36 : 8 : 48mC : mH : mO = 9 : 2 : 12%C = (36/92)*100% = 39,1%%H = (8/92)*100% = 8,7%%O = (48/92)*100% = 52,2%2) C3H5(OH)3 + 3KOH -----> C3H5(OK)3 + 3H2O
1.
C3H5(OH)3= m.cz.= 3*12u + 8*1u + 3*16u= 36u + 8u + 48u = 92u
36u= C
8u= H
48u= O
92u ---- 100%
36u ---- x
____________
x= 36u * 100%/ 92u= ok. 39,13% C
8u ---- x
x= 8u * 100%/ 92u= ok. 8,69% H
100% -39,13% - 8,69%= ok. 52,18% O
2. C3H5(OH)3 + 3KOH -> C3H5(OK)3 + 3H2O
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1) mC3H5(OH)3=36u+8u+48u=92u
mC : mH : mO = 36 : 8 : 48
mC : mH : mO = 9 : 2 : 12
%C = (36/92)*100% = 39,1%
%H = (8/92)*100% = 8,7%
%O = (48/92)*100% = 52,2%
2) C3H5(OH)3 + 3KOH -----> C3H5(OK)3 + 3H2O
1.
C3H5(OH)3= m.cz.= 3*12u + 8*1u + 3*16u= 36u + 8u + 48u = 92u
36u= C
8u= H
48u= O
92u ---- 100%
36u ---- x
____________
x= 36u * 100%/ 92u= ok. 39,13% C
92u ---- 100%
8u ---- x
____________
x= 8u * 100%/ 92u= ok. 8,69% H
100% -39,13% - 8,69%= ok. 52,18% O
2. C3H5(OH)3 + 3KOH -> C3H5(OK)3 + 3H2O
produktami są glicerolan potasu i woda