1.Oblicz Pole wycinka koła i długość łuku, jeżeli:
a) r= 5cm i α = 60º
b) r= 8cm i α = 45º
2.Oblicz
=
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a) 60°/360° = 1/6
x= 1/6 * 2π * 5 = 1⅔ π
60°/360° = 1/6
Pw = 1/6 *π * 5² = 1/6 * π * 25 = 25/6π = 4 i 1/6π
b) 45°/360° = 1/8
x= 1/8 * 2π * 8 = 2π
45°/360° = 1/8
Pw= 1/8 *π * 8² = 1/8 *π * 64 = 8π
zad.2.
√2 i 1/4 = √9/4
√9/4 = 3/2
a) r= 5cm i α = 60º
Pole wycinka:
P=60/360 * πr²
P=1/6*π*25cm²=4¹/₆π cm²
długosc łuku:
l=1/6*2πr
l=1/6*10πcm=1⅔πcm
b) r= 8cm i α = 45º
P=45/360*π*64cm²=8πcm²
l=45/360*2π*8cm=2πcm
√2¼ = √9/4 = 3/2 = 1,5