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2r=10 ---> r=5
h=5
P=2×πr² = 2×π×5²= 50π cm²
V=πr²×h = π×5²×5=125π cm³
2
zbyt mało danych
3
r=5
h=8
l=√(r²+h²) = √(5²+8²}=√89
P=πr²+πrl = 5²π + 5π×√89 = 25π+5√89 π = (25+√89)π j²
V=1/3πr²×h = 1/3π×5²×8 = 200π/3 j³