1.Oblicz Gestosc klocka przyjmujac mase równą 24g , a rozmiary (2 cmx 3cm x 5cm ) 2. Oblicz ciśnienie 5 klocków na powierzchnie 6cm2
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m = 24 g
a = 2 cm
b = 3 cm
c = 5 cm
V = a*b *c = 2*3*5 = 30 cm3
d = m/V = 24 g/ 30 cm3 = 4/5 g/cm3 = 0,8 g/cm3
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m = 5 * 24 g = 120 g = 0,12 kg
g = 10 N/kg
S =6 cm2 = 6:10 000 m2 = 0,0006 m2
F = Fg = m*g = 0,12 kg*10 N/kg = 1,2 N
p - ciśnienie
p = F/S = 1,2 N/ 0,0006 m2 = 12000/6 Pa = 2000 Pa = 2 kPa
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Myślę, że pomogłam :-)