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d=7cm
r=3,5 cm
L=2πr
L=2π 3,5=7π
2.
2πr=12π
2r=12 /2
r=6cm
3.r=8
P=πr^
P= 64π
7cm : 2 = 3.5 cm <- promień
P= πr2
P= π*3,5. 2(kwadrat)
P= 12,25 π
2.jaki promień ma koło o obwodzie 12 π cm
Ob=2πr | :2π
r= ob : 2π
r= 12π : 2π
r= 6
3.oblicz pole koła o promieniu 8 cm
P=πr2
P=64π
dł okręgu 2πr =2π3,5=7πcm
2. 12π=2πr/:2π
6=r 6 cm
3. P=πr²
P=π8²
P=64π cm²