Question

1.jika 3n+1=A. anggota pada A ={1,2,3,5,6,7,8,9}. nilai n yang memenuhi adalah...

tolong beserta caranya

Answer 1

Caranya dicoba satusatu.. Jika a=1 3n+1=1 3n=1-1 3n=0 n= 0 jika a =2 3n+1=2 3n=2-1 3n=1 n=1/3 jika a =3 3n+1=3 3n=3-1 3n=2 n=2/3 jika a =4 3n+1=4 3n=4-1 3n=3 n=1 jika a =5 3n+1=5 3n=5-1 3n=4 n=4/3 = 1 1/3 dst

Answer 2

3n + 1 = A . A={1,2,3,4,5,6,7,8,9}
untuk A = 1
3n + 1 = 1
3n = 0
n = 0
untuk A=2
3n + 1 = 2
3n = 1
n 1/3
untuk B = 3
3n + 1 = 3
3n = 2
n= 2/3 

dilihat dari sifat diatas, berrati n = {0, 1/3, 2/3, 1, 4/3, 5/3, 2, 7/3, 8/3}