Wyznacz dziedzinę funkcji f.
a) f(x)=√(x³-5x²+3x+9)
b) f(x)= 1/[√(18x³-3x²-4x+1)]
a)
x³-5x²+3x+9≥0
(x+1)(x²-6x+9)≥0
(x+1)(x-3)²≥0
D: x∈<-1;+∞)
b)
18x³-3x²-4x+1>0
(x+1/2)(x²-2/3x+1/9)>0
(x+1/2)(x-1/3)²>0
D: x∈(-1/2;1/3)u(1/3;+∞)
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a)
x³-5x²+3x+9≥0
(x+1)(x²-6x+9)≥0
(x+1)(x-3)²≥0
D: x∈<-1;+∞)
b)
18x³-3x²-4x+1>0
(x+1/2)(x²-2/3x+1/9)>0
(x+1/2)(x-1/3)²>0
D: x∈(-1/2;1/3)u(1/3;+∞)