Penjelasan dengan langkah-langkah:
Luas = 12
Alas = 3+√7
Tinggi= ....?
[tex]Luas = \frac{1}{2}( luas \: alas \: \times \: tinggi ) \\ 12 = \frac{1}{2} (3 + \sqrt{7} ) \times tinggi \\ 24 = (3 + \sqrt{7} )t \\ t = \frac{24}{3 + \sqrt{7} } \\ t = \frac{24}{3 + \sqrt{7} } \times \frac{3 - \sqrt{7} }{3 - \sqrt{7} } \\ t = \frac{24(3 - \sqrt{7} )}{9 - 7} \\ t = \frac{24(3 - \sqrt{7} )}{2} \\ t = 12(3 - \sqrt{7} )[/tex]
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Penjelasan dengan langkah-langkah:
Luas = 12
Alas = 3+√7
Tinggi= ....?
[tex]Luas = \frac{1}{2}( luas \: alas \: \times \: tinggi ) \\ 12 = \frac{1}{2} (3 + \sqrt{7} ) \times tinggi \\ 24 = (3 + \sqrt{7} )t \\ t = \frac{24}{3 + \sqrt{7} } \\ t = \frac{24}{3 + \sqrt{7} } \times \frac{3 - \sqrt{7} }{3 - \sqrt{7} } \\ t = \frac{24(3 - \sqrt{7} )}{9 - 7} \\ t = \frac{24(3 - \sqrt{7} )}{2} \\ t = 12(3 - \sqrt{7} )[/tex]