Question

1.6 log 2 x 2log 5 x 5log 36 ???
2. 1per2 log 2 +4log 16 - 3log 9 ???
3. akar 3 log 9 + 3 log 81 ???
4. 3log 1per9 - 3log 1per27 ???
5. log 24 +log 1per2 - log12 ??
6. log akar20 - log 4 + log akar 2 ???

kak bantuin ..

Answer 1

1. 6'log2 . 2'log5 . 5'log36
= 6'log36
= 2

2. (1/2)' log 2 + 4'log16 - 3'log9
= -2 + 2 - 2
= -2

3. (V3)' log 9 + 3' log 81
= 4 + 4
= 8

4. 3' log (1/9) - 3' log (1/27)
= -2 - (-3)
= -2 + 3
= 1

5. log24 + log(1/2) - log12
= log (24 /(2 . 12))
= log 1
= 0