Question

Znajdź liczbę , której 38% wynosi (1 i jedna/ trzecia ) do kwadratu - pierwiastek 1 i 9 /16

Pomóżcie na jutro

Jakim procentem liczby 2 *(5 1/16 +3 1/16) jest liczba pierwiastek pierwiastek 81* PIERWIASTEK 16

Answer 1

Zadanie 1

(1 i jedna/ trzecia ) do kwadratu - pierwiastek 1 i 9 /16 =
= (4/3)² - √25/16 =
= 16/9 - 5/4 =
= 64/36 - 45/36 =
= 19/36

19/36 ---- 38%
x ---------- 100%

x = 19/36 * 100% / 38%
x = 475/9 / 38%
x = 475/9 * 1/38%
x = 19/18
x = 1 i 1/18

========================================
Zadanie 2

2 *(5 1/16 +3 1/16) =
= 2 * (81/16 + 49/16) =
= 2 * 130/16 =
= 2 * 8 i 2/16 =
= 2 * 8 i 1/8 =
= 2 * 65/8 =
= 65/4 =
= 16 i 1/4 = 16,25

pierwiastek 81* PIERWIASTEK 16 =
= 9 * 4 =
= 36

36 ------ 100%
16,25 -- x%

x = 16,25 * 100% / 36
x = 1625/36%
x = 45,13(8)%

Answer 2

(1⅓)² - √(1 ⁹/₁₆) = (⁴/₃)² - √(²⁵/₁₆) = ¹⁶/₉ - ⁵/₄ = ⁶⁴/₃₆ - ⁴⁵/₃₆ = ¹⁹/₃₆

 

19/36 ----- 38%
x ---------- 100%

x = 19/36 * 100/38
x = 475/9 / 38
x = 475/9 * 1/38
x = 19/18
x = 1 i ¹/₁₈

 

Zadanie 2.

 

2 *(5 1/16 +3 1/16) = 2*(8 ²/₁₆) = 16 ⁴/₁₆ = 16¹/₄ = 16,25

√81*√16 = 9*4 = 36

36 / 16,25 *100% ≈ 221,5%