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Área inicial = x²
Perímetro modificado = 4x-40
P = 4L
L = (4x-40)/4 = x-10
A = (x-10)²
(x-10)² = 9/16 x²
x²-20x+100 = 9/16 x²
16x² - 320x + 1600 = 9x²
16x²-9x²-320x+1600 = 0
7x² -320x+1600 = 0
(7x-280)(7x-40)/7=0
(x-40)(7x-40) =0
x-40=0 7x-40=0
x=40 x = 40/7
Perímetro inicial = 4x = 4*40 = 160 m
Perímetro inicial =4*(40/7) = 160/7 = 22.857 m; no cumple ya que no se puede restar los 40 m
Por tanto el perímetro inicial es 160 m