Question

150 punktów CHEMIA ENTALPIA ! :d zadania w załączniku

Answer 1

6)
ΔHx = -3ΔH₁ - ΔH₂
ΔHx = -3*226,75 -(-49,04)
ΔHx = -631,21 kJ/mol

7)
ΔHx = -2ΔH₁ + 4ΔH₂ - ΔH₃
ΔHx = -2*(-143,86) + 4(-563,45) - (-513,1)
ΔHx = -1452,98 kJ/mol

8)
ΔHx = -ΔH₁ - ΔH₂ + ΔH₃
ΔHx = -180,74 - (-112,96) + 9,37
ΔHx = -58,41 kJ/mol

9)
ΔHx = -ΔH₁ + ¹/₂ΔH₂ + ¹/₂ΔH₃
ΔHx = -(-74,85) + ¹/₂(-164) + ¹/₂(-184,6)
ΔHx = -99,45 kJ/mol

10)
ΔHx = -ΔH₁ + ΔH₂ + ¹/₂ΔH₃
ΔHx = -8,08 + (-385,2) + ¹/₂(-571,68)
ΔHx = -679,12 kJ/mol

11)
ΔHx = ΔH₁ - ΔH₂ + ΔH₃
ΔHx = -164 - (-821,8) + (-742,47)
ΔHx = -84,67 kJ/mol