ikbalwahyu
Data itu kn hasil percobaan, maka kita harus menggunakn rata2 volume nya(Ca(OH)2) percobaan (1+2+3)/3 10+9+11 = 30/3 = 10ml M1V1 x valensi H = M2V2 x valensi OH 0,1.20 x 1 = M2.10 x 2 M2 = 0,2/20 = 0,1 M M = n/V 0,1 = n/0,01 n = 0,001 mol = gr/Mr gr = 0,001 x 74 = 0,074 gram (B) semoga bermanfaat :D
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Amaldoft
Diket: *n HNO3 = 20 mL x 0,1 M = 2 mmol = 0,002 mol *Volume Ca(OH)2 rata-rata = 10+9+11/3 = 10 mL *Mr Ca(OH)2 = 74
Ca(OH)2 = HNO3 V1 x M1 x valensi basa = V2 x M2 x valensi asam 10 mL x M1 x 2 = 20 mL x 0,1 M x 1 20M1 = 2 M1 = 0,1 M
percobaan (1+2+3)/3
10+9+11 = 30/3 = 10ml
M1V1 x valensi H = M2V2 x valensi OH
0,1.20 x 1 = M2.10 x 2
M2 = 0,2/20 = 0,1 M
M = n/V
0,1 = n/0,01
n = 0,001 mol = gr/Mr
gr = 0,001 x 74 = 0,074 gram (B)
semoga bermanfaat :D
*n HNO3 = 20 mL x 0,1 M = 2 mmol = 0,002 mol
*Volume Ca(OH)2 rata-rata = 10+9+11/3 = 10 mL
*Mr Ca(OH)2 = 74
Ca(OH)2 = HNO3
V1 x M1 x valensi basa = V2 x M2 x valensi asam
10 mL x M1 x 2 = 20 mL x 0,1 M x 1
20M1 = 2
M1 = 0,1 M
n Ca(OH)2 = 0,1 M x 10 mL
= 1 mmol
= 0,001 mol
Massa (g) = 0,001 mol x 74
= 0.074 gram (A)