Jawaban:
B
Penjelasan:
5 liter gas N2 bermassa 5,6 g
12,5 L gas CO (Ar C =12, O=16).
n N2= 5,6/28=0,2.
n CO= ??.
n N2 = V N2.
n CO. V CO.
0,2 = 5.
mol. 12,5
5 X= 2,5
mol= 2,5/5= 0,5
JP= mol x L
JP= 0,5 mol x 6,02 x 10^23
JP= 3,01 x 10^23
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Jawaban:
B
Penjelasan:
5 liter gas N2 bermassa 5,6 g
12,5 L gas CO (Ar C =12, O=16).
n N2= 5,6/28=0,2.
n CO= ??.
n N2 = V N2.
n CO. V CO.
0,2 = 5.
mol. 12,5
5 X= 2,5
mol= 2,5/5= 0,5
JP= mol x L
JP= 0,5 mol x 6,02 x 10^23
JP= 3,01 x 10^23