Question

15. Diketahui vektor p=( -4 4 0) dan q=(-1 5 1) besar sudut antara p dan q Adalah....​

Answer 1

Penjelasan dengan langkah-langkah:

V E K T O R

p=( -4 4 0)

q=(-1 5 1)

p × q = (–4)×(–1) + 4×5 + 0×1

p × q = 4 + 20 + 0

p × q = 24

|p| = √(-4)²+4²+0² = √32 = 4√2

|q| = √(–1)²+5²+1² = √27 = 3√3

|p||q| = 4√2 × 3√3

|p||q| = 12√6

sudut antara p dan q = ∅

cos ∅ = p × q

|p||q|

cos ∅ = 24

12√6

cos ∅ = 2

√6

cos ∅ = 2√6

6

cos ∅ = ⅓√6

∅ = arc.cos (⅓√6)

∅ = 35,26°