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Verified answer
VEKTOR15a][
F1 = -3 i + 5 j
F2 = 7 i + 6 j
F3 = 10 j - 2 j
__________ +
R = (14 i + 9 j) km
15b][
∆x = 40 cos 60° + 10
∆x = 30 km
∆y = 40 sin 60° - 10√3
∆y = 10√3 km
Perpindahan
r = ∆x i + ∆y j
r = 30 i + 10√3 j
besar r
|r| = √(30² + (10√3)²(
|r| = √1200 = 20√3 km ←
arah r
tan α = 10√3 / 30
tan α = ⅓√3
α = 30° ←