(1+√5)² + (1-√5)² =
a²+b²
to jest takie proste a nie mogę tego ogarnąć, cały czas coś pomijam..
CO RAZY CO?
(1+√5)² + (1-√5)² = 1+2√5+5 + 1-2√5+5 = 1+1+5+5=12
(1+√5)² + (1-√5)² = 1² + 2·1·√5 + (√5]²+ 1² - 2·1· (-√5) + (-√5) ² = 1+2√5+5+1-2√5+5=12
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(1+√5)² + (1-√5)² = 1+2√5+5 + 1-2√5+5 = 1+1+5+5=12
(1+√5)² + (1-√5)² = 1² + 2·1·√5 + (√5]²+ 1² - 2·1· (-√5) + (-√5) ² = 1+2√5+5+1-2√5+5=12