Respuesta:
si no me equivoco son polinomios y monomios espero haberte ayudado
[tex]4\left(a+5\right)\left(a-3\right)\\\\=4\left(a^2+2a-15\right)\\\\=4a^2+4\cdot \:2a+4\left(-15\right)\\\\=4a^2+8a-60[/tex]
[tex]\left(x^2+1\right)\left(x^2-1\right)\left(x^2+1\right)\\\\=\left(x^2-1\right)\left(x^2+1\right)^{1+1}\\\\=\left(x^2-1\right)\left(x^2+1\right)^2[/tex]
[tex]m\left(m-4\right)\left(m-6\right)\left(3m+2\right)\\\\=m\left(m^2-10m+24\right)\left(3m+2\right)\\\\=3m^2m^2+3m^2\left(-10m\right)+3m^2\cdot \:24+2mm^2+2m\left(-10m\right)+2m\cdot \:24\\\\=3m^4-28m^3+52m^2+48m[/tex]
[tex]3x\left(x^2-2x+1\right)\left(x-1\right)\left(x+1\right)\\\\=3x\left(x^2-2x+1\right)\left(x^2-1\right)\\\\=\left(3x^3-3x\right)\left(x^2-2x+1\right)\\\\=3x^3x^2+3x^3\left(-2x\right)+3x^3\cdot \:1-3xx^2-3x\left(-2x\right)-3x\cdot \:1\\\\=3x^5-6x^4+6x^2-3x[/tex]
[tex]\left(x-3\right)\left(x+4\right)\left(x-5\right)\left(x+1\right)\\\\=\left(x^2+x-12\right)\left(x^2-4x-5\right)\\\\=x^2x^2+x^2\left(-4x\right)+x^2\left(-5\right)+xx^2+x\left(-4x\right)+x\left(-5\right)-12x^2-12\left(-4x\right)-12\left(-5\right)\\\\=x^4-3x^3-21x^2+43x+60[/tex]
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Verified answer
Respuesta:
si no me equivoco son polinomios y monomios espero haberte ayudado
[tex]4\left(a+5\right)\left(a-3\right)\\\\=4\left(a^2+2a-15\right)\\\\=4a^2+4\cdot \:2a+4\left(-15\right)\\\\=4a^2+8a-60[/tex]
[tex]\left(x^2+1\right)\left(x^2-1\right)\left(x^2+1\right)\\\\=\left(x^2-1\right)\left(x^2+1\right)^{1+1}\\\\=\left(x^2-1\right)\left(x^2+1\right)^2[/tex]
[tex]m\left(m-4\right)\left(m-6\right)\left(3m+2\right)\\\\=m\left(m^2-10m+24\right)\left(3m+2\right)\\\\=3m^2m^2+3m^2\left(-10m\right)+3m^2\cdot \:24+2mm^2+2m\left(-10m\right)+2m\cdot \:24\\\\=3m^4-28m^3+52m^2+48m[/tex]
[tex]3x\left(x^2-2x+1\right)\left(x-1\right)\left(x+1\right)\\\\=3x\left(x^2-2x+1\right)\left(x^2-1\right)\\\\=\left(3x^3-3x\right)\left(x^2-2x+1\right)\\\\=3x^3x^2+3x^3\left(-2x\right)+3x^3\cdot \:1-3xx^2-3x\left(-2x\right)-3x\cdot \:1\\\\=3x^5-6x^4+6x^2-3x[/tex]
[tex]\left(x-3\right)\left(x+4\right)\left(x-5\right)\left(x+1\right)\\\\=\left(x^2+x-12\right)\left(x^2-4x-5\right)\\\\=x^2x^2+x^2\left(-4x\right)+x^2\left(-5\right)+xx^2+x\left(-4x\right)+x\left(-5\right)-12x^2-12\left(-4x\right)-12\left(-5\right)\\\\=x^4-3x^3-21x^2+43x+60[/tex]