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dane;
c0s=12/13
wzóry;
cos=b/c
sin=a/c
tg=a/b
ctg=b/a
cos=12/13
więc;
b=12
c=13
a=?
a²+12²=13²
a²+144=163
a²=25
a=5cm
sin=5cm/13cm=5/13
tg=5cm/12cm=5/12
ctg=12cm/5cm=12/5
sin^2 + cos^2 = 1
sin^2 + (12/13)^2 = 1
sin^2 + 144/169 = 1
1 - 144/169 = sin^2
169/169 - 149/169 = sin^2
25/169 = sin^2
sin = 5/13
tg = sin/cos
tg = 5/13/13/12
tg = 5/13 * 13/12
tg = 5/12
ctg = 1/tg
ctg = 12/5