Dik. segitiga ABC dengan BC = 6 cm, tan A = 4/3, dan cos B = 12/13, maka panjang AC adalah....
fatihahalhusna
Tan A = 4/3 sin A = 4/5 cos B = 12/13 sin B = 5/13 AC/sinB = BC/sin A AC = BC/sin A .sin B = 6/(4/5) .(5/13) = 6.5/4 . 5/13 = 150/52 = 2,885 cm
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fatihahalhusna
Terimakasih kak atas koreksinya, kalo masih ada yang salah dikoreksi ya kak
cos B = 12/13 sin B = 5/13
AC/sinB = BC/sin A
AC = BC/sin A .sin B = 6/(4/5) .(5/13) = 6.5/4 . 5/13 = 150/52 = 2,885 cm