Question

Cos B = 12/13, maka nilai sin B adalah...

Answer 1

Cos = sa : mi
cos = 12 : 13
* mi^2 = sa^2 + de^2
13^2 = 12^2 + de^2
169 = 144 + de^2
de^2 = 169 - 144
de^2 = 25
de = 5

* sin = de : mi
sin B = 5 : 13