Question

Mohon bantuannya ... jika a dan B kedua sudutnya lancip dan diket. sin a = 3/5 dan cos B = 12/13, hitung lah tan(a B)....

Answer 1

Sin A = 3/5 --> tan A = 3/4
cos B = 12/13 --> tan B = 5/12
tan (A+B) = (tan A + tan B)/ ( 1 - tan A tan B)
= (3/4 + 5/12) / ( 1- 3/4 . 5/12)
= (7/6)/(11/16)
= 56/33