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1+2+3+.........+50
⇔ n (bilangan terakhir)= 50
a (Bilangan pertama)
b (beda) = 2-1
= 1
S (jumlah keseluruhan bilangan)
⇔ Nih rumusnya : Sn=1/2n (2a + (n-1) × b)
jadi, 1+2+3+.........+50
⇔ S50= 1/2 × 50 ( 2×1 + (50-1) ×1)
= 25 (2+ 49)
= 25 × 51
= 1275
Kalau gak pingin pake rumus gini
1 + 2 + 3+.........+50
50+49+48+..........+1 +
51+51+51+.........+51= 50×51
2
=1275
semoga bisa membantu