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1+2+3+...+n = n(n+1)/2
Sehingga,
1+2+3+...+100 = 100(100+1)/2
1+2+3+...+100 = 50 x 101
1+2+3+...+100 = 5.050
b=1
n=100
Sn=n/2(a+Un)
S100=100/2 (1+100)
S100=50.101
=5.050