Question

1.22 Oblicz:

zadanie w załączniku (liczby)

Answer 1

a) 4⁻³ · (0,125)⁻³ = (4 · 0,125)⁻³ = (½)⁻³ = 2³ = 8

b) (2,5)⁻² · (0,2)⁻² · (⅔)⁻² = (5/2)⁻² · (⅕)⁻² · (⅔)⁻² = (5/2 · ⅕ · ⅔)⁻² = (⅓)⁻² = 3² = 9

c) (⅔)⁻⁴ · (¾)⁻⁴ = (⅔ · ¾)⁻⁴ = (½)⁻⁴ = 2⁴ = 16

d) 2⁻³ · 3⁻³ · (1/12)⁻³ = (2 · 3 · 1/12)⁻³ = (½)⁻³ = 2³ = 8

e) 5⁻⁷ · 4⁻⁷ · (0,05)⁻⁷ = (5 · 4 · 0,05)⁻⁷ = 1⁻⁷ = 0,0000001

f) 2⁰ · 5⁰ : (1/13)⁰ = 1 · 1 : 1 = 1