12:2.................. 28:2.................... prostokąt ma obwód 100 mm a z pierwszego ma 31 mm a z drugiego................................. prostokąt ma obwód 100 mm a z drugiego ma 45 ile ma z pierwszego......................................
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12:2 = 6
28:2 = 14
Ob = 100 mm a = 31
Ob = 2a + 2b
100 = 2 * 31 + 2b
100 = 62 + 2b
100 - 62 = 2b
38 = 2b |/2
b = 19
Ob = 100 a = 45
Ob = 2a + 2b
100 = 90 + 2b
100 - 90 = 2b
10 = 2b |/2
b = 5
12/2 = 6
28/2 = 14
a = 31
O = 100 mm
O = 2a + 2b obwód prostokąta
100 = 2 * 31 + 2b
100 = 62 + 2b
100 - 62 = 2b
38 = 2b |/2
b = 19
O = 100 a = 45
O = 2a + 2b obwód prostokąta
100 = 90 + 2b
100 - 90 = 2b
10 = 2b obustronie przez dwa czyli 10:2=5 a 2:2b =b i otrzymujemy b =5