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substitusikan f(a ).= 1- 3a ke g(x)
sehingga diperoleh
(1-3a)^2 -1=3
1-6a+9a^2 - 1 = 3
9a^2 -6a-3 = 0 ... faktorkan
(3a+1)(a-1) = 0
jadi ,, a = -1/3 ATAU a=1