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Verified answer
DINAMIKAm = 4 kg
F = 20 N, cos θ = 0,8
a = 0,5
μₖ = __?
gaya gesekan
fₖ = μₖ N = μₖ m g
jika g = 10 m/s²
ΣF = m.a
F cos θ - μₖ m g = m a
20 • 0,8 - μₖ • 4 • 10 = 4 • 0,5
16 - 40 μₖ = 2
14 = 40 μₖ
μₖ = 14/40 = 7/20 = 0,35 ✓
jika diambil g = 9,8 m/s²
ΣF = m.a
F cos θ - μₖ m g = m a
20 • 0,8 - μₖ • 4 • 9,8 = 4 • 0,5
16 - 39,2 μₖ = 2
14 = 39,2 μₖ
μₖ = 14/39,2= 5/14 = 0,357 ✓