Question

-100-99-98-...-2-1-0+1+2+...+48+49+50 tolong jawab pake cara yaa

Answer 1

#Deret Aritmatika
-100-99...+50
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Sn = -100-99...-1-0+1... +50

nilai positif hanya pada interval 1-50, sedangkan negatif pada interbal 1-100, maka : ↓

= -100-99..-1-0+1..+50
= -100-99..-51 + (-50...-1-0+1...+50)
= -100-99...-51
= - (100+99..+51)
= - Sn
a = 100
b = -1

Un = a + (n-1)b
51 = 100 +(n-1)-1
-49 = -n +1
n = 49+1
n = 50

-Sn = (50/2)(100+51)
-Sn = 25(151)
-Sn = 3775
Sn = 3775/-1
Sn = -3775

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Kesimpulan :
" -100-99...+49+50 = -3775 "
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