Suma 40 % pewnej liczby i 25 % drugiej liczby wynosi 340.Różnica 3/4 pierwszej liczby i 2/10 drugiej liczby wynosi 370. Jakie to liczby ?
(uklad równań)
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0,4a+0,25b = 340 |*4
0,75a-0,2b = 370
1,6a+b = 1360
0,75a-0,2b = 370
b = -1,6a+1360
0,75a-0,2*(-1,6a+1360) = 370
b = -1,6a+1360
0,75a+0,32a-272 = 370
b = -1,6a+1360
0,75a+0,32a = 370+272
b = -1,6a+1360
1,07a = 642 |:1,07
b = -1,6a+1360
a = 600
b = -1,6*600+1360
a = 600
b = -960+1360
a = 600
b = 400
a = 600
{0,4a+0,25b=340 |*100
{0,75a-0,2b=370 |*100
{40a+25b=34000 |*4
{75a-20b=37000 |*5
{160a+100b=136000
{375a-100b=185000
_____________________
535a=321000
a=600
{a=600
{40a+25b=34000
{a=600
{24000+25b=34000
{a=600
{25b=10000
{a=600
{b=400