Question

1). (x+1)²+2(x+1)-8=0 2). (2x-3)²-4(2x-3)-12=0

Answer 1

1)
misalkan x + 1 = a
a² + 2a - 8 = 0 ------------> (a - 2)(a + 4) = 0
a = 2              a = -4
x + 1 = 2      x + 1 = -4
x = 1              x = -5

2)
misalkan 2x - 3 = a
a² - 4a - 12 = 0      ---------------> (a - 6)(a + 2) = 0
a = 6                        a = -2
2x - 3 = 6              2x - 3 = -2 
x = 9/2                    x = 1/2