Określ dziedzinę funkcji:
a) f(X)= log₂ X/1-x (w podstawie 2)
b) f(x)= log x²-1 (x²-2x-3) (W podstawie jest x²-1)
a)x/(1-x) >0 i 1-x ≠0x*(1-x)>0 i x≠1x∈(0, 1)
b)x^2-1>0 i x^2-1≠1 i x^2-2x-3>0(x-1)(x+1)>0 i x≠√2 i x≠-√2 i (x+1)(x-3)>0
x∈(-∞, -1)u(1, +∞) i x≠√2 i x≠-√2 i x∈(-∞,-1)u(3, +∞)
Odp: x∈(-∞, -√2)u(-√2, -1)u(3, +∞)
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a)x/(1-x) >0 i 1-x ≠0
x*(1-x)>0 i x≠1
x∈(0, 1)
b)x^2-1>0 i x^2-1≠1 i x^2-2x-3>0
(x-1)(x+1)>0 i x≠√2 i x≠-√2 i (x+1)(x-3)>0
x∈(-∞, -1)u(1, +∞) i x≠√2 i x≠-√2 i x∈(-∞,-1)u(3, +∞)
Odp: x∈(-∞, -√2)u(-√2, -1)u(3, +∞)