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V walca = πr²h
Pole podstawy walca = πr² = π4² = 16π cm²
Vs1(Objętość 1 stożka) = 1/3 * 16π * 3 = 16π cm³
Vs2(Objętość 2 stożka) = 1/3 * 16π * 6 = 2 * 16π = 32π cm³
Vs1 + Vs2 = 16π + 32π = 48π cm³
Odp. Figura w walcu ma V = 48π cm³.