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H=9cm
H1=3cm
H2=6cm
H1+H2 =3+6=9cm =H
Vs=πr²H objętość walca
Vs=πr²H/3 objętośc stożka
Vs=4²*9π/3
Vs=16*3π
Vs=48π cm³ objętośc stożków razem,